The age of two friends anii and biju differ by 3 years . Ani's father dharam is twice as old as ani and biju is twice as old his sister cathy. The age s of Cathy and dharam differ b by 30 year s find the age of qni and biju....???
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ani's age = a
biji's age = b
ani's father, dharma's age = d
cathy's age = c
A/q
a-b =3____(1)
d=2a__(2)
b= 2c
c= b/2____(3)
d-c = 30____(4)
putting value of (2) and (3) in 4
2a - (b/2) = 30
⇒4a -b = 60____(5)
now subtracting (1) and (5), we get,
a = 19 years
b = 19-3 = 16 years
anji's age = 19 years
biji's age = 16 years
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cRAZY pRINCE
Anonymous:
how u have done so fast..?
Answered by
1
Hey mate here is your answer:-
Let ,
The age of Anii be 'w'
The age of biji be 'x'
The age of Cathy be 'y'
The age of Anii's father be 'z'
A/q
w - x = 3 .......... i
z = 2a...............ii
x = 2y
= y = x÷2..........iii
z - y = 30-4......iv
putting the value of of equation 1 and 3 in 4
2w - (x/2) = 30
4w - x = 60 .......... v
now ,subtracting King equation 1 AND 5 we get
w = 19years
x =19-3= 16 years
Anii age = 19 yrs
Biji age = 16 years
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