Math, asked by Anonymous, 11 months ago

The age of two friends anii and biju differ by 3 years . Ani's father dharam is twice as old as ani and biju is twice as old his sister cathy. The age s of Cathy and dharam differ b by 30 year s find the age of qni and biju....???

Answers

Answered by Anonymous
17

ani's age = a

biji's age = b

ani's father, dharma's age = d

cathy's age = c

A/q

a-b =3____(1)

d=2a__(2)

b= 2c

c= b/2____(3)

d-c = 30____(4)

putting value of (2) and (3) in 4

2a - (b/2) = 30

⇒4a -b = 60____(5)

now subtracting (1) and (5), we get, 

a = 19 years

b = 19-3 = 16 years

anji's age = 19 years

biji's age = 16 years

________________________________

cRAZY pRINCE


Anonymous: how u have done so fast..?
Anonymous: hehehe...That's pRINCE style
Anonymous: xd..ok.. but really I want to know
Anonymous: Sorry
Anonymous: now tell
Anonymous: Enough
Anonymous: ok fine..no need of ur answer anymore..
Answered by kriti0
1

Hey mate here is your answer:-

Let ,

The age of Anii be 'w'

The age of biji be 'x'

The age of Cathy be 'y'

The age of Anii's father be 'z'

A/q

w - x = 3 .......... i

z = 2a...............ii

x = 2y

= y = x÷2..........iii

z - y = 30-4......iv

putting the value of of equation 1 and 3 in 4

2w - (x/2) = 30

4w - x = 60 .......... v

now ,subtracting King equation 1 AND 5 we get

w = 19years

x =19-3= 16 years

Anii age = 19 yrs

Biji age = 16 years

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