Math, asked by shivanshupadhyay753, 5 months ago

the age of two person for by 20 year if the five year ago the in elder one be 5 times as old as the younger one their present age ​

Answers

Answered by annsarahjoy2008
3

Answer:

10 yrs

Step-by-step explanation:

Let the age of Older one be x

The age of Younger be y

The difference in age is x−y=20

x=y+20

5 years ago ages will be y+15,y−5

The elder one is 5 times younger one

So y+15=5(y−5)

y+15=5y−25

4y=15+25

4y=40

y=10

So the age of younger one is 10 yrs

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Answered by Salmonpanna2022
2

Answer:

Age of elder one =30 years

Age of younger one =10 years

Step-by-step explanation:

Let the age of elder one be X years

then the age of younger one be X-20 years

since their age diffrence is 20 years

now five years ago their ages would be

Elders age X-5 years

and youngers age X-20-5=X-25 years

now elders age is 5 times the youngers age in five years ago

=>X-5=5(X-25)

=>X-5=5X-125

=>125-5=5X-X

=>120=4x

=>X=120/4

=>X=30 years

Elder's present age=30 years

Younger's present age=30-20=10 years

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