Question

the ages of a and b are in ratio 5:7.after four years sum of their ages is will be 116.what are there present age​

Answer 1

• Given

• Ratio of ages of a and b = 5 : 7
• Sum of their ages after four years = 116

• To find

• Their present ages

• Solution

Let the ages of a and b be 5x and 7x respectively.

Their ages after four years -

• Age of a = 5x + 4
• Age of b = 7x + 4

According to the question,

⟶ 5x + 4 + 7x + 4 = 116

⟶ 12x + 8 = 116

⟶ 12x = 116 - 8

⟶ 12x = 108

⟶ x = 108/12

⟶ x = 9

The value of x = 9

Their present ages -

• Present of a = 5x = 5 × 9 = 45 years
• Present of b = 7x = 7 × 9 = 63 years

________________________________

Let's verify -

The sum of the ages of a and b after four years = 116.

So,

Put the value of x in 5x + 4 + 7x + 4

⟶ 5 × 9 + 4 + 7 × 9 + 4

⟶ 45 + 4 + 63 + 4

⟶ 116

Hence, verified.

Answer 2

Answer:

$\huge{ \mathbb{➩ Given : - }}$

Ratio of ages of a and b = 5 : 7

Ratio of ages of a and b = 5 : 7 Sum of their ages after four years = 116

$\huge \bf{ \underline{ \underline{➩To \: find }}}$

Their present ages

$\huge \bf{ \underline{ \underline{ Solution }}}$

Let the ages of a and b be 5x and 7x respectively.

Their ages after four years -

Age of a = 5x + 4

Age of a = 5x + 4 Age of b = 7x + 4

A.T.Q

$\sf➩ 5x + 4 + 7x + 4 = 116$

$\sf➩ 12x + 8 = 116$

$\sf➩ 12x = 116 - 8$

$\sf➩ 12x = 108$

$\sf➩ x = \frac{108}{12}$

$\sf➩ x = 9$

The value of x = 9

Their present ages -

Present of a = 5x = 5 × 9 = 45 years

Present of b = 7x = 7 × 9 = 63 years.

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