Math, asked by ndasgupta1982, 19 days ago

the ages of A and B are presently in the ratio of 3 ratio 5. 9 years ago the ratio was 12 free to 23. what will be the present age of a​

Answers

Answered by khushi200805
2

Answer:

A=33

Step-by-step explanation:

Ratio of present ages of B and A = 5x : 3x

According to the question

⇒ (5x - 9)/(3x - 9) = 23/12

⇒ 12 (5x - 9) = 23 (3x - 9)

⇒ 60x - 108 = 69x - 207

⇒ 69x - 60x = 207 - 108

⇒ 9x = 99

⇒ x = 11

= 3x=3×11=33

Answered by jyotidas463
1

Step-by-step explanation:

Let the sum of the ages of A=5x and B=3x

Then after 6 years, their ages are in ratio 7:5

∴ 5x+6 = 7

3×+6 = 5

∴ 25x+30=21x+42

4x=12

x=3

Present age of A= 5x=15

Present age of B=3x=9

Sum of present age =15+9=24 years

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