Math, asked by khyodabamang3914, 9 months ago

The ages of Aatif and Aasif are in the ratio of 5:7. Four years from now the ratio of their ages will be 3:4. Find their present ages.

Answers

Answered by Anonymous
7

Question

The ages of Aatif and Aasif are in the ratio of 5:7. Four years from now the ratio of their ages will be 3:4. Find their present ages.

Solution

Given :-

  • The ages of Aatif and Aasif are in the ratio of 5:7.
  • Four years from now the ratio of their ages will be 3:4.

Find :-

  • Age of Aatif & Aasif .

Explanation

Let,

  • Age of Aatif = x years
  • Age of Aasif = y years

A/C to question

(The ages of Aatif and Aasif are in the ratio of 5:7. )

==> x : y = 5 : 7

==> x/y = 5/7

==> 7x - 5y = 0 ---------------Equ(1)

Again,

( Four years from now the ratio of their ages will be 3:4. ).

==> (x + 4) : (y + 4) = 3 :4

==> (x+4)/(y+4) = 3/4

==> 4*(x+4) = 3*(y+4)

==> 4x - 3y = 12 - 16

==> 4x - 3y = -4

Or,

==> 4x - 3y = -4 ------------Equ(2)

Multiply , by 5 in equ(2) & 3 in equ(1)

  • 21x - 15y = 0
  • 20x - 15y = -20

______________Sub. it's

==> 21x - 20x = 20

==> x = 20

Keep value of x in equ(2)

==> 4 * (20) - 3y = - 4

==> 3y = -4 - 80

==> y = - 84/3

==> y = - 28

But, we know

Age be always positive .

So, (-ve) sign is negligible

Hence

  • Age of Aatif (x) = 20 years
  • Age of Aasif (y) = 28 years.

__________________

Answered by BrainlyAnswerer0687
25

Given

  • Ratio of age of Aatif and Aasif = 5 : 7

  • Ratio of age of Aatif and Aasif after four years = 3 : 4

To Find

  • Present age of Aatif.

  • Present age of Aasif

Solution :

Let, the multiple of ratio be x

age of Aatif and Aasif after four years = 3 : 4

5x + 4 : 7x + 4 = 3 : 4

20x + 16 = 21x + 12

16 - 12 = 21x - 20x

4 = x

Present age of Aatif = 5x

Present age of Aatif = 5 × 4

→ Present age of Aatif = 20

Present age of Aasif = 7x

Present age of Aasif = 7 × 4

⇒ Present age of Aasif = 28

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