The ages of four brothers of a family are in ap the eldest brother age is 17th years and age difference between eldest brother and youngest brother is 9 years find the ages
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if the eldest brother's age is 17.
and the difference betwen eldest and youngest brother is 9.
i.e. the age of youngest brother is 8
if their ages are in ap then difference between their ages should be constant.
9/3 = 3 .
the age of eldest brother = 17 years
the age of second brother = 17- 3 = 14 years
the age of third brother = 14-3 = 11 years
the age of youngest brother = 8 years
and the difference betwen eldest and youngest brother is 9.
i.e. the age of youngest brother is 8
if their ages are in ap then difference between their ages should be constant.
9/3 = 3 .
the age of eldest brother = 17 years
the age of second brother = 17- 3 = 14 years
the age of third brother = 14-3 = 11 years
the age of youngest brother = 8 years
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