Math, asked by harmanjotk623, 19 days ago

the ages of John and David are in ratio 5:7.Four years later the sum of their ages will be 56 years. what are their present ages?​

Answers

Answered by adritabarmanroy
0

Answer:

The ages of John and David are 20 and 28 respectively.

Step-by-step explanation:

Let the ages of John and David be 5x and 7x respectively.

Four years later they are (5x+4) and (7x+4) respectively.

By the question,

(5x+4)+(7x+4)=56

or, 12x+8=56

or, 12x=48

or,x=4

So, the age of John=5x

=20

And the age of David =7x

=28

Answered by Tan90ismyname
0

Answer:

John = 20 years & David = 28 years

Step-by-step explanation:

Let the present ages of John and David be x

So x/x = 5/7

5x - 7x = 0

So 4 years later that is (5x+4) + (7x+4) = 56

5x + 7x = 56 - 8

5x + 7x = 48

12 x = 48

x = 4

So 5 x = 20 & 7x = 28

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