Question

The ages of Leena and heena are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.

Answer 1

Answer:

Question -

●The ages of Leena and heena are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.

Given -

•The age of Leena and Heena are in the ratio 7 : 5.

•Ten years hence, the ratio of their ages will be 9 : 7.

To find -

•their present ages

Solution -

•Let the present ages of Leena and Heena be 7 : 5

•After 10 yrs, their age will be 7x+10 and 5x+10

•According to the given condition,

(7x + 10) : (5x + 10) = 9 : 7

i.e. $\frac{7x+10}{5x+10} = \frac{9}{7}$

9(5x+10) = 7(7x + 10)

45x+90 = 49x + 70

49x - 45x = 90-70

4x =  20

x = 5

∴Present age of Leena= 7x = 7×5= 35 years

∴Present age of Heena= 5x = 5×5 = 25 years