The ages of Leena and Heena are in the ratio 7 : 5. Ten years hence , the ratio of their ages will be 9 : 7 . Find their present ages .
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Answers
The ages of Leena and Heena are in the ratio 7:5. Ten years hence, the ratio of their ages will be 9:7. What are their present ages?
Answer :- Let the rational between ages of Leena and Heena be x
The ages of Leena and Heena are in the ratio 7:5.
Thus there ages are, Leena 7x and Heena 5x
Ten years hence, the ratio of their ages will be 9:7.
10 year hence their ages will be
Leena’s age 7x + 10
Heena’s age 5x + 10
The ratio of their ages
7x + 10 / 5x + 10 = 9 / 7
Cross multiplication
9 ( 5x + 10 ) = 7 ( 7x + 10 )
45x + 90 = 49x + 70
45x - 49x = 70 - 90
—5x = -20
5x = 20
x = 20/5
x = 4
The rational is 4
Their respective ages
Leena’s age 7x = 7 × 4 = 28 years
Heena’s age 5x = 5 × 4 = 20 years
Answer :- the Leena’s age is 28 years and Heena’s age is 20 years.
Step-by-step explanation:
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