Question

The ages of leena and heena are in the ratio of 5: 3 Ten years hence, the ratio of their age will be 7:5. Find then present ages​

Answer 1

Step-by-step explanation:

Required Answer:-

Given that:-

The ages of Leena and Heena are in the ratio of 5: 3 .

Ten years hence, the ratio of their age will be 7:5.

Present Age = ?

$\boxed{\sf{Let's \ Find \ out! }}$

• Let the age constant be x.
• So Leena's age is 5x and Heena, 3x

• Ten years hence:-

$\sf{\dfrac{5x+10}{3x+10} = \dfrac{7}{5}}$

$\sf{5(5x+10) = 7(3x+10)}$

$\sf{25x+50 = 21x+70}$

$\sf{25x-21x = -50+70}$

$\sf{4x = 20}$

$\huge{\boxed{\sf{x = 5}}}$

Now, we will multiply x with 5 to find Leena's age

= 5 × 5 = 25 years

Now, we will multiply x with 3 to find Heena's age.

= 3 × 5 = 15 years.

So, Leena and Heena's ages are 25 and 15 years respectively .

Answer 2

Question:-

●The ages of leena and heena are in the ratio of 5: 3 Ten years hence, the ratio of their age will be 7:5. Find then present ages.

Given :-

•The age of Leena and Heena are in the ratio of 5:3

•Ten years hence, the ratio of their age will be 7:5

To find :-

•their present ages

Solution :-

•Let the present age of Leena and Heena be 5x and 3x

•After 10 yrs , their age will be (5x+10) and (3x+10)

According to the given condition,

(5x + 10) : (3x + 10) = 7 : 5

i.e

$\frac{5x + 10}{3x + 10} = \frac{7}{5}$

5(5x+10) = 7(3x+10)

25x + 50 = 21x + 30

25x - 21x = 50 - 30

4x = 20

x= 5

•Present age of Leena= 5x = 5×5 = 25 yrs

•Present age of Heena= 3x = 3×5 = 15 yrs