Question

The ages of sheena and meena are in the ratio 5:7 four years later the sum of their ages will be 56 years . what are their present ages
pls guys tell​

Answer 1

Let the age of sheena and meena be x and y respectively.

According to the question:

==> x/y = 5/7

==> 7x = 5y

==> 7x - 5y = 0 ...(1)

Also,

After 4 years:

==> x + 4 + y + 4 = 56

==> x + y = 56 - 8

==> x + y = 48 ...(2)

Multiply (2) by 5

==> 5x + 5y = 240 ...(3)

Adding (1) and (3)

==> 7x - 5y + 5x + 5y = 240 + 0

==> 12x = 240

==> x = 240/12

==> x = 20

Putting value of x in (2)

==> x + y = 48

==> 20 + y = 48

==> y = 48 - 20

==> y = 28

Hence, Age of sheena is 20 years and age of meena is 28 years.

Answer 2

Step-by-step explanation:

let the common multiple be x

present age of sheena is 5x

present age of Meena is 7x

After 4years,

Sheena age is 5x+4

Meena age is 7x+4

Given that:

5x+4+7x+4=56

12x+8=56

12x=56-8

x= 48/12

x=4

Present age of Sheena is 5x= 5*4= 20 years

Present age of Meena is 7x = 7*4=28 years

FOLLOW ME GUYS ..ANSWER IS CORRECT