Math, asked by krishnakant4, 1 year ago

The ages of suman and neelam are in ratio 3:4. 4 year ago, their ages were in ratio 5:7 find their age

Answers

Answered by kritag
78
given ratio = 3/4
so the present age of suman be = 3x
and the present age of neelam be = 4x
now according to question,
4 years ago age of suman = 3x -4
4 years ago age of neelam = 4x -4
and now their ages ratio ( 4 years ago) become = 5/7
on comparing
3x-4/ 4x -4 = 5/7
we get
x = 8
so,
the age of suman = 24 yrs,
and the age of neelam = 32 yrs.
Answered by priyoshi1
45
let the ratio of the ages of suman and neelam be 3x:4x

there ages 4 years ago was 3x-4 and 4x -4 respectively

=>3x-4 /4x-4 = 5/7
=>21x - 28 =20x - 20
=>21x - 20x=28 -20
=>x=8

therefore ,
present age of suman is 3x =3*8=24 yrs
and neelam is 4x=4*8 =32 yrs.

May this help you.....
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