The ages of three friends are consecutive integers. If their three consecutive ages have a sum of 192, what is the age of the oldest friend?
Answers
Answer:
Answer:
Age of oldest friend = 65 years
Explanation:
Let, ages of three friends be,
x , x + 1 , x + 2
(These three are consecutive integers.)
Where, x is the age of the youngest friend.
x + 1 is the age of the middle age friend. and
x + 2 is the age of oldest friend.
According to the question,
→ Sum of ages of all friends = 192
so,
→ ( x ) + ( x + 1 ) + ( x + 2 ) = 192
→ x + x + 1 + x + 2 = 192
→ 3 x + 3 = 192
→ 3 x = 192 - 3
→ 3 x = 189
→ x = 189/3
→ x = 63
Therefore,
Age of the oldest friend would be,
→ x + 2 = 63 + 2 = 65 yrs
Hence,
Age of oldest friend would be 65 years.
Answer:
Answer:
Age of oldest friend = 65 years
Let, ages of three friends be,
x , x + 1 , x + 2
(These three are consecutive integers.)
Where, x is the age of the youngest friend.
x + 1 is the age of the middle age friend. and
x + 2 is the age of oldest friend.
According to the question,
Sum of ages of all friends = 192
so,
- ( x ) + ( x + 1 ) + ( x + 2 ) = 192
- x + x + 1 + x + 2 = 192
- 3 x + 3 = 192
- 3 x = 192 - 3
- 3 x = 189
- x = 189/3
- x = 63
Therefore,
Age of the oldest friend would be,
- x + 2 = 63 + 2 = 65 yrs
Hence,
Age of oldest friend would be 65 years.