Question

The ages of two brothers differ by 16 years ago the elder one was 3 times as old as the younger one what is the present age of the elder brother

Answer 1

Answer:

30

Step-by-step explanation:

Age of younger brother is taken as x and that of elder brother is taken as (x+16)

6 yrs before:

=>> 3(x-6) = (x+16-6)

=>> 3x-18 = x+10

=>> 2x = 28

=>> x= 14

Therefore age of :

Elder brother = (x+16) = (14+16) = 30

Younger brother = x = 14

Hope it will help you

Answer 2

Hiii friends..

Here is your answer..

Explanation:

Let the age of younger person is x,

Then elder person age is (x+16)

=> 3(x-6) = (x+16-6) [6 years before]

=> 3x-18 = x+10

=> x = 14.