Math, asked by neelabh70, 1 year ago

the ages of two person are in ratio 5:7. eighteen years ago their ages were in ratio 8:13. find their present ages

Answers

Answered by DeshiChhora
75
Let the present ages of two persons be 5x and 7x years Age of two persons 18 years ago are (5x – 18) and (7x – 18) years Given (5x – 18)/(7x – 18) = 8/13 13(5x – 18) = 8(7x – 18) 65x – 234 = 56x – 144 9x = 90 Therefore, x = 10 Thus age of the two persons are 50 and 70 years.

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Answered by prachee17
23

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