The ages of two persons A and B are in the ratio 7:5 .Ten years hence,the ratio of their ages will be 9:7.Find their ages.
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Answered by
6
A : B = 7 : 5
A = 7x
B = 5x
10 years:
A = 7x + 10
B = 5x + 10
(7x + 10)/(5x + 10) = 9/7
9(5x + 10) = 7(7x + 10)
45x + 90 = 49x + 70
4x = 20
x = 5
A = 7x = 7(5) = 35
B = 5x = 5(5) = 25
Answer: A = 35, B = 25
Answered by
0
HEY Buddy.....!! here is ur answer..
Let the present age of A is 7x and B is 5x
Given that after 10 years the ratio of their ages will be 9:7
Then, According to the question...
(7x+10)/(5x+10) = 9/7
=> 49x+70 = 45x+90
=> 49x–45x = 90–70
=> 4x = 20
=> x = 5
Thus the present ages of A = 7x = 7×5 = 35 yrs
and B = 5x = 5×5 = 25yrs
I hope it will be helpful for you..!!
THANK YOU ✌️✌️
Let the present age of A is 7x and B is 5x
Given that after 10 years the ratio of their ages will be 9:7
Then, According to the question...
(7x+10)/(5x+10) = 9/7
=> 49x+70 = 45x+90
=> 49x–45x = 90–70
=> 4x = 20
=> x = 5
Thus the present ages of A = 7x = 7×5 = 35 yrs
and B = 5x = 5×5 = 25yrs
I hope it will be helpful for you..!!
THANK YOU ✌️✌️
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