Question

The ages of two persons differ by 16 years. If 6 years ago the elder one be 3 times as old as the younger one. Find their present ages.

Answer 1

Step-by-step explanation:

younger 's present age=x

older present age =x+16

6years ago =(x-6)

6years ago =(x+16-6)

3(x-6)=x+16-6

3x-18=x+10

2x=28 x=14

younger present age =14

older present age =14+16= 30

Answer 2

Answer:

Step-by-step explanation:

Given :-

The ages of two persons differ by 16 years.

If 6 years ago the elder one be 3 times as old as the younger one.

To Find :-

Their present ages.

Solution :-

Let the age of the younger person be x years.  

According to the question

age of the elder person = (x + 16) years.  

⇒ 3 (x - 6) = (x + 16 - 6)  

⇒ 3x -18 = x + 10  

⇒ 2x = 28

⇒ x = 14.  

Hence, their present ages are 14 years and 30 years.