the algebraic form of an arithematic sequence is 4n+1 whats its first
term
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The sequence is 5 ,9,13.. Hence, the first term is 5. => d = 4
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The general form is 4n+1
Let n=1,2,3,4……
Therefore, The first 4 terms are,
A1= 4(1)+1 = 4+1 =5
A2= 4(2)+1 =9
A3= 4(3)+1 =13
A4= 4(4)+1 =17.
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