Question

The alleilic frequency of recessive allele is 0.4. Find out the number of heterozygous individuals in a population of 500
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Answer 1

We are given q= 0.4

And we know that p+ q = 1

Therefore....p = 0.6

Now for heterozygous individuals

2pq = 2*0.6*0.4

= 0.48

No. Of heterozygous individuals =

0.48*500

= 240.......