the allelic frequency of recessive allele is 0.4 find out the number of heterozygous individuals in a population of 500
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Answered by
6
Answer:
0.37 is the answer.
Explanation:
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Answered by
18
We are given q= 0.4
And we know that p+ q = 1
Therefore....p = 0.6
Now for heterozygous individuals
2pq = 2*0.6*0.4
= 0.48
No. Of heterozygous individuals =
0.48*500
= 240
Hope you understand
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