The almost of zinc required to produce 224ml of H2 at STP on treatment with dilute H2SO4 will be(Zn=65)
Answers
Answered by
5
Solution :
Zinc reacts with sulfuric acid according to the following formula :
Zn+H2SO4→ZnSO4+H2Zn+H2SO4→ZnSO4+H2
Therefore 1 mole of zinc reacts to give 1 mole of hydrogen
Volume of 1 mole of hydrogen at STP is 224000ml224000ml
1 mole of Zn is 65 grams
Therefore 0.65 grams of zinc reacts to give 224 ml of hydrogen
plz follow me
Zinc reacts with sulfuric acid according to the following formula :
Zn+H2SO4→ZnSO4+H2Zn+H2SO4→ZnSO4+H2
Therefore 1 mole of zinc reacts to give 1 mole of hydrogen
Volume of 1 mole of hydrogen at STP is 224000ml224000ml
1 mole of Zn is 65 grams
Therefore 0.65 grams of zinc reacts to give 224 ml of hydrogen
plz follow me
Similar questions