the altitude and the base of a triangular field are in the ratio 6:5. If its cost is ₹ 49,57,200at the rate of ₹ 36,720 per hectare and 1 hectare is 10,000 sq. m, find dimensions of the field ( in metre)
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let the altitude of field be h and base be b
Thus h:b = 6:5
h= 6/5 b
area of field = 1/2 b*h
in hectares, area of field = (1/10000)*1/2*bh
According to question
Cost of 1 hectare = 36,720 rupees
and total cost is 49,57,200 rupees
Thus,
Total cost = cost of 1 hectare * total area
49,57,200= 36.720 * (1/20000) bh
putting h = 6/5b
49,57,200 = 36,720 * (1/20000) 6/5b^2
b^2 = 123.456
b= 11.11 m
thus h= 6/5 * 11.11
h = 1.2*11.11
h = 13.332 m
Thus h:b = 6:5
h= 6/5 b
area of field = 1/2 b*h
in hectares, area of field = (1/10000)*1/2*bh
According to question
Cost of 1 hectare = 36,720 rupees
and total cost is 49,57,200 rupees
Thus,
Total cost = cost of 1 hectare * total area
49,57,200= 36.720 * (1/20000) bh
putting h = 6/5b
49,57,200 = 36,720 * (1/20000) 6/5b^2
b^2 = 123.456
b= 11.11 m
thus h= 6/5 * 11.11
h = 1.2*11.11
h = 13.332 m
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