The altitude at which the weight of a body is only 64% of its weight on the surface of earth is
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Answer:
h = 1.6×10^6 m
Explanation:
Let h be the height at which weight of the body is 64 % of its weight on earth. W' = 64W/100.
g' = g [R/(R+h)]²
[(R+h)/R]^2 = g/g'
(h/R + 1)^2 = mg / mg'
(h/R + 1)^2 = W / W'
(h/R + 1)^2 = W / (64W/100)
(h/R + 1)^2 = 100/64
h/R + 1 = 10/8
h/R = 1.25 - 1
h/R = 0.25
h = 0.25 R
h = 0.25 × 6.4×10^6
h = 1.6×10^6 m
Hence, altitude is 1.6×10^6 m.
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