The altitude of a right triangle is 7 cm less rhen it's base . If the hypotanios is 13 cm . Then find its other two sides.
Answers
Answer:
let other sides be x and x-7
acc. to question :( x) ^2 +(x-7) ^2= (13) ^2
x^2+x^2+49-14x= 169
2(x^2) +14x = 120
x^2 +7x =60
x^2+7x-60 =0
x^2+10x-3x-60 = 0
x(x+10) -3(x+10) = 0
(x-3) = 0; x=3
(x+10) =0 ; x=-10
Since side cannot be negative x=3
Therefore, the sides are 3 cm and 10 cm.
Given,
- Altitude of right triangle is 7 cm less than its base.
- Hypotenuse is 13 cm.
To find,
- The other two sides.
Solution,
Let x be the base of the triangle
Then altitude will be (x-7)
We know that,
So, by pythagoras theorem,
So, x = 12 or x = -5
Since,the side of a triangle cannot be negative,so the base of the triangle is 12 cm.
And the altitude will be (12-7) = 5 cm