The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.
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S O L U T I O N :
Let,
- The base of a right Δ is R cm.
- The altitude of a right Δ be (R - 7) cm.
- The hypotenuse of a right Δ be 13 cm.
According to the Pythagoras theorem,
Base ² + Altitude² = Hypotenuse²
[ Put the values ]
⇒ R² + (R - 7)² = 13²
⇒ R² + R² + 49 - 14R = 169
⇒ 2R² - 14R - 120 = 0
⇒ R² - 7R - 60 = 0
⇒ R² - 12R + 5R - 60 = 0
⇒ R(R - 12) + 5(R - 12) = 0
⇒ (R - 12) (R + 5) = 0
⇒ R = 12 , -5
[ Note :- Ignoring negative term ]
⇒ R = 12 cm
Therefore,
- The base of a right Δ is 12cm.
- The altitude of a right Δ is 5cm.
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