Question

The altitude of a triangle is 6cm greater than its base. If its area is 108cm². Find its base and height

Answer 1

Hi friend,

Here's your answer,


See the attached file for the answer


Hope it helps!!!!

#yashankΠsingh

Answer 2

Answer:

Step-by-step explanation:

Let the base of the triangle= x cm, then altitude of the triangle will be=(6+x)cm.

Also, area of the triangle=$108cm^{2}$, then

⇒$\frac{1}{2}{\times}base{\times}height=108$

⇒$\frac{1}{2}{\times}x{\times}(6+x)=108$

⇒$x^{2}+6x=216$

⇒$x^{2}+6x-216=0$

⇒$x^{2}+18x-12x-216=0$

⇒$x(x+18)-12(x+18)=0$

⇒$(x-12)(x+18)=0$

⇒$x=12$ (Neglecting the negative sign)

Therefore, the base of the triangle= x cm=12 cm, and  altitude of the triangle=(6+x)cm=6+12=18cm