The altitude of a triangle is two-third the length
of its corresponding base. If the attitude increased
by 4 cm and the base decreased by 2 cm, the area
of the triangle remains the same. Find the base and allitude of rectangle
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Answer:
Step-by-step explanation:
Let the base=xcm
altitude=2/3xcm
area of triangle=1/2×base×height
=1/2×x×2/3x
=1/2×2/3x2cm2(1)
area=1/2(x-2)(2x+12/3)_(2)
1÷2×2÷3x2=1÷2(x-2)(2x+12÷3)
2x2=1÷2(x-2)(2x+12÷3)×2×3
2x2=(x-2)(2x+12)
2x2=2x2+12x-4x-24
2x2=2x2+8x-24
2x2-2x2-8x=-24
-8x=-24
x=24÷8
=3
so,base=3cm
and,altitude=2/3x
=2/3×3
=2cm.
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