Question

The average of 33 numbers is 74. The average of the first 17 numbers is 72.8 and that of the last 17
numbers is 77.2. If the 17th number is excluded, then what will be the average of the remaining
numbers (correct to one decimal place)?

Answer 1

Answer:

150

Step-by-step explanation:

150

72.8+77.2=150

Answer 2

Average would be 72.9.

Step-by-step explanation:

Given,

Numbers = 33,

Their average = 74,

So, sum = numbers × average = 33 × 74 = 2442,

Now if numbers average of the first 17 numbers = 72.8,

Sum of first 17 numbers = 17 × 72.8 = 1237.6,

Also, average of last 17 numbers = 77.2,

Sum of last 17 numbers = 17 × 77.2 = 1312.4,

Thus, 17th number = (sum of first 17 numbers + sum of last 17 numbers ) - total sum

= 1237.6 + 1312.4 - 2442

= 108,

If this number is excluded,

Then new sum = 2442 - 108 = 2334,

Numbers = 33 - 1 = 32,

Hence, new average = $\frac{\text{Sum}}{\text{Numbers}}=\frac{2334}{32}=72.9375\approx 72.9$

#Learn more:

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