Question

the altitude of a triangular field is one third of its base if the cost of sowing the field at rupees 58 per hectare is rupees 783 then its altitude is

Answer 1

Let the altitude be x meters.

Now, Altitude = x, therefore the base = 3x.

Therefore, by 1/2bh,

     Area = $3x^{2}$/2 $m^2$
or, (783/58)*1000 = tex]3x^{2} [/tex]/2 $m^2$
or, x = 300m

Answer 2

Dear Student,

◆ Answer -

h = 300 m

● Explaination -

Let h be altitude of the triangular field.

Cost of sowing the field is given by -

Cost of sowing = area of field × rate per hectare

783 = area of field × 58

Area of field = 783 / 58

Area of field = 13.5 hectare

Area of field = 135000 sq.m

But area of triangle is calculated by -

Area of field = 1/2 × b × h

135000 = 1/2 × 3h × h

135000 = 3h^2 / 2

h^2 = 135000 × 2/3

h^2 = 90000 m^2

h = 300 m

Hence, altitude of the triangular field is 300 m.

Thanks dear. Hope this helps you...