The altitude of aright angle triangle is 5cm more than its base if it's area is 150cm find the base n altitude of a triangle
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Step-by-step explanation:
let the Base of triangle is x
then altitude is x+5
Area of triangle = 1/2 × Base × height
150cm= 1/2 × (x) ×(x+5)
300 = x^2 + 5x
x^2 + 5x - 300 = 0
x^2 + 20x - 15x - 300 = 0
x (x+20) - 15 (x+ 20) = 0
(x-15)(x-20) = 0
x = 15 , 20
If Base =15 cm then altitude =20 cm
if Base =20cm then altitude =25cn
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