Question

The altitude of right angle triangle is 100cm and the greatest side is 2m . Find the cost to paint it at the rate of 15 per square metre.

Answer 1

Given :-

• The altitude of right angle triangle is 100cm and the greatest side is 2m.

To find :-

• The cost to paint it at the rate of 15 per square metre.

Solution :-

• Altitude of right angle triangle = 100cm = 100/100 = 1m

• Greatest side = hypotenuse = 2m

According to Pythagoras theorem

→ h² = p² + b²

→ (2)² = (1)² + b²

→ 4 = 1 + b²

→ b² = 4 - 1

→ b² = 3

→ b = √3 m

As we know that

→ Area of triangle = ½ × b × h

Where " b " is base and " h " is height of the triangle.

• According to the given condition

→ Area of trianlge

→ ½ × b × h

→ ½ × √3 × 2

→ √3m²

→ 1.73 m²

Now,

The cost to paint it at the rate of 15 per square metre.

→ Total cost to paint 1.73m² triangle

→ 15 × 1.73

→ Rs.25.95

Answer 2

Answer:

$\large\underline{\underline{\mathfrak{\color{lime}{Given :-}}}}$

• The altitude of right angle triangle is 100cm .

• the greatest side is 2m .

• rate of 15 per square metre.

$\large\underline{\underline{\mathfrak{\color{blue}{To \: Find :-}}}}$

• Find the cost to paint

$\large\underline{\underline{\mathfrak{\color{red}{Solution :-}}}}$

$\boxed{ \sf \orange{base = root \: of (h \: square - a \: square)}}$

$\sf \to \: base =10$

$\sf \to \: area = \frac{1}{2} \times bh$

$\sf \to \: 10 \times 100 \\ \\ </p><p> \sf \to \: 1000 \: {cm}^{2} \\ \\ </p><p> \sf \to \: 0.1 \\ </p><p>$

$\mathfrak{ \sf{cost \: of \: polishing} } \sf =0.1 \times 15 \\ \\ \: \mathfrak{ \red{cost \: of \: polishing} } \: = \sf \: 1.5rs</p><p>$