The altitudeAD of a triangle ABC in which CA obtuse and AD is equal to 10 cm if BD is equal 10 cm and CD is equal to 10 root 3 cm determine angle A
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Answer:
angle A is105degree
Step-by-step explanation:
The altitude AD of ΔABC in which ∠A obtuse and AD = 10 cm. If BD = 10 cm and CD = 10
3
cm, determine ∠A.
November 22, 2019avatar
Afroze Raichand
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ANSWER
ΔABC is a right triangle , right angled at D such that = 10 cm and BD = 10 cm
∴tan∠BAD=
AD
BD
⇒tan∠BAD=
10
10
=1
⇒tan∠BAD=tan45
∘
TRIGONOMETRICRATIOS
⇒∠BAD=45
∘
ΔACD is a right triangle right angled at D such that AD = 10 cm and DC = 10
3
cm.
∴tan∠CAD=
AD
CD
⇒tan∠CAD=
10
10
3
=
3
⇒tan∠CAD=tan60
∘
∴∠CAD=60
∘
From (i) and (ii) , we have
∠BAC=∠BAD+∠CAD=45
∘
+60
∘
=105
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