The AM of 15 observations is 9 and the AM of first 9 observations is 11 and then AM of
remaining observations is?
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Answer:
Step-by-step explanation:Mean of 11 observations =50
Mean of first 6 =49
Last 6 =52
Total sum of observation =50×11=550
Total observation of first 6 =49×6
=294
Total observation of last 6 =52×6
=312
Sixth observation =294+312−550
=606−550
=56
Answered by
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Answer mean 56.....use Am formula
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