Question

the AM of two numbers a and b exceeds their GM by 40 and HM is 36. Then the value of a and b are

Answer 1

Step-by-step explanation:

We have A−G=1.5 and G−H=1.2

Also we now H=AG2

Thus, we get G−AG2=1.2

⇒AG(A−G)=1.2

⇒5G=4A and also A−G=1.5

∴A=7.5,G=6

Hence we get the numbers to be 12,3

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Answer 2

Answer:

12,3

Step-by-step explanation:

A−G=1.5 and G−H=1.2

Also we now H=AG2

Thus, we get G−AG2=1.2

⇒AG(A−G)=1.2

⇒5G=4A and also A−G=1.5

∴A=7.5,G=6

Hence we get the numbers to be 12,3

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