The amount of acetic acid present in 100 ml of 0.1 M solution is
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Concentration = 1.0molL−1
Volume = 100mL
Moles of HOAc = 0.10 mol L−1
Concentration = nV.
So n=C×V.
Thus,
0.1L×1.0molL−1
=0.1mol
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Concentration = 1.0molL−1
Volume = 100mL
Moles of HOAc = 0.10 mol L−1
Concentration = nV.
So n=C×V.
Thus,
0.1L×1.0molL−1
=0.1mol
HOPE IT HELPS YOU.....!!❤❤
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