Math, asked by mlkulkarni1968, 5 days ago

The amount of air present in a cylinder when a vacuum pump removes 1/4 of the air remaining in the cylinder at a time

Answers

Answered by mirnafees464
0

Answer:

let the volume of air present in cylinder = x

on removing of 1/4 part x, we have

x-1/4x = 4x²- 1 = 4x

4x²-4x-1=0

x = {-4 ± √ 4²- 4×4(-1)}/2×4

x = (-1 + √ 2)/2

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