the amount of air present In a cylinder when a vacuum pump removes 1/4 of the air remaining in the cylinder at a time
. It is an AP question pls send first 4 terms
Answers
Answered by
1
this is not in ap
let the initial volume is v
after first time the volume will be (3/4)*v
after second time 3/4*3/4 *v = 9 /16 v
after third time = 3/4*9/16 v = 27/64 v
after forth time = 3/4*27/64 v = 81/216 v
the common difference is not same here so or is not in ap
let the initial volume is v
after first time the volume will be (3/4)*v
after second time 3/4*3/4 *v = 9 /16 v
after third time = 3/4*9/16 v = 27/64 v
after forth time = 3/4*27/64 v = 81/216 v
the common difference is not same here so or is not in ap
Similar questions