Question

The amount of Arsenic pentasulphide that can be obtained when 35.5 g of arsenic acid treated with excess H2S in the presence of conc. HCl (assuming 100% conversion) is

Answer 1

Answer:

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Answer 2

QUESTION:-

The amount of Arsenic pentasulphide that can be obtained when 35.5 g of arsenic acid treated with excess H2S in the presence of conc. HCl (assuming 100% conversion) is

ANSWER:-

Arsenic acid has a molar mass of 142 g/mol. 35.5 g of arsenic acid corresponds to 

 14235.5=0.25 moles.

 2H3AsO4H2SHClAs2S5

The amount of arsenic pentasulfide that can be obtained is 

 20.25=0.125 mol

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