The amount of CH NH, dissolve in 2l of water so that it produces concentration OH- is equal to
5*10-M, is - [Given K of CH NH, = 2 x 10°)
(a) 5.6 gm
(b) 3.88 gm
(c) 7.75 gm
(d) 8.3 gm
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The answer for this quesrion is (b)3.88
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