Question

The amount of charge passed in time t through a cross-section of a wire is Q{t) = At^2 + Bt + C. (a) Write the dimensional formula for A, B and C. (b) If the numerical values of A, B and C are 5, 4 and 3 respectively in SI units, find the value of the current at t = 5sec

Answer 1

Answer:

Explanation:

Sol.

Q(t) = At^2 + Bt + c a)

At^2 = Q ⇒ A = Q/t^2 = ‘T’/T^-2 = A 1^T^-1 b)

Bt = Q ⇒ B = Q/t = A ‘T’/T = A

c) C = [Q] ⇒ C = A’T’

d) Current t = dq/dt = d/dt(At^2 + Bt + C) = 2At + B = 2 * 5 * 5 + 3 = 53 A.