The amount of electricity that can deposit 108g of silver from silver nitrate solution is
Answers
Answered by
67
Ag+ + e- ---> Ag
108 g of Ag is one mole of silver. One Faraday is one mole of electrons.
From the equation above, you can see that one mole of Ag+ requires 1 mole of electrons to deposit 1 mole of Ag metal.
108 g of Ag is one mole of silver. One Faraday is one mole of electrons.
From the equation above, you can see that one mole of Ag+ requires 1 mole of electrons to deposit 1 mole of Ag metal.
Answered by
20
Answer:
Ag^+ + e--> Ag
Explanation:
Eag=Atomic mass/1=108
No.of faraday=Wag/Eag
=108/108
=1 Faraday
HOPE IT WILL HELP YOU....
MARK ME AS BRAINLIEST!!!
Similar questions