Question

the amount of heat produced on complete burning of 10 kg of a given fuel in pure oxygen equals H kilojoule. the calorific value of that fuel would equal ?​

Answer 1

Answer:

$\frac{H}{10}\ Kilojoule/kg\ \ OR\ \ 0.10H\ Kilojoule/kg$ is the Calorific value of the given fuel.

Explanation:

First of all, let us have a look at the definition of Calorific Value of a fuel.

Calorific value of a fuel is defined as the amount of Heat produced by burning 1 kg of fuel in the presence of pure oxygen or air.

We are given that Mass of fuel = 10 kg

Amount of heat produced = H Kilojoule

As per definition of calorific value:

$\text{Calorific Value} = \dfrac{\text{Heat Produced on burning}}{\text{Weight of fuel}}$

Putting the value of heat produced and weight of fuel to find its calorific value:

$\text{Calorific Value} = \dfrac{H}{10}\ Kilojoule/kg$

OR

$\text{Calorific Value} = 0.10H\ Kilojoule/kg$

So, the answer is:

$\frac{H}{10}\ Kilojoule/kg\ \ OR\ \ 0.10H\ Kilojoule/kg$ is the Calorific value of the given fuel.

Answer 2

Explanation:

We know 

Mass of fuel× calorific value=mass of water ×specific heat ×temperature difference

Given mass of fuel mf=10 kg and mass of water m = 2kg

ΔT=700−200=500C

Specific heat of water =4.186J/grams0C=4.186×10−3J/kg0C 

Now putting the above values in the equation we get 

CV=102×4.186×10−3×(70−20)=4.186×10−2 J/kg