Question

The amount of heat required to convert 1 g of ice at
0°C into steam at 100°C, is
(1 716 cal.
(3) 180 cal.
(2) 500 cal.
(4) 100 cal.​

Answer 1

Answer:

option 3

Explanation:

because the temperature of ice and that will be converted to a cal so that the temperature is 180

Answer 2

The required "option 1) 716 cal." is correct.

Explanation:

To find, the quantity of heat required =

Heat required to melt 1 g of ice at 0°C to water at 0°C

= 1 g × 80 calorie per gram = 80 calorie

Heat required to raise the temperature of 1 g of water from 0°C to 100°C

= 1 g × 1 calorie/g/1°C rise of temperature × 100°C

= 100 calorie

Heat required to convert water at 100°C to steam at 100°C

= 1 g× 536calorie/g = 536 calorie.

∴Total heat required

= 80 calorie + 100 calorie + 536 calorie

= 716 calorie

Hence, the required option 1) 716 cal. is correct.