Question

The amount of
heat required to convert 10 gm of ice at - 5°C to water at 75°C is (Latent heat of fusion
ofice = 80 cal gm latent heat of vaporization of water = 540 cal/gm, specific heat of water = 1 cal/gm "Cand specific heat of ice = 0.5 cal/gm/°C]
a) 1575 cal
b) 1557 cal
c) 1755 cal
d) 5175 cal​

Answer 1

Answer:

convert 1.25 dag to cg ​

Step-by-step explanation:

convert 1.25 dag to cg ​