The amount of heat required to convert 10gm of ice into water at 20°C is
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Answer:
Heat energy needed = energy required to convert ice to water+ energy required to rise the temperature of water from zero to 20 degree celcius. The Latent Heat of Fusion for ice is 384J/gram. So 10 grams of ice require: 10X384 = 3840J of energy.
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Answer:
Heat energy needed = energy required to convert ice to water+ energy required to rise the temperature of water from zero to 20 degree celcius.
The Latent Heat of Fusion for ice is 384J/gram.
So 10 grams of ice require:
10X384 = 3840J of energy.
The specific heat capacity of water is:
4.184J/g/°C.
10g water from 0°C to 20°C require:
10X20X4.184 = 836.8J
Total energy required
= 3840 + 836.9
= 4676.9J
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