Question

The amount of heat required to raise the temperature of 50 gm of water from 0 to 100

Answer 1

Given,
mass = 50gm = 0.05kg
specific heat (s) of water = 1
∆θ = T2- T1 = 100 - 0 = 100°C

We will use the formula
Heat (q) = ms∆θ
q = 0.05 × 1 × 100
q = 5J

Hope this helps..

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Answer 2

Question:-

What is the amount of heat required to raise the temperature of 50 gm of water from 0°C to 100°C?

Solution:-

Given,

Mass of water = 50 grams

Change in temperature=∆T = (100°C - 0°C) => 100°C

We know that,

Specific heat of water is 1

So, By using the formula

Q = ms∆T

Substituting all values in the equation, we get

$Q = (50)(1)(100)$

$Q = 5000$

The heat energy required = 5000 cal

(or) 5 K Cal (In CGS units)