Question

The amount of MgS formed when 2g Mg reacts with 2g S is:

Answer 1

2g of mdg will be formed

Answer 2

Mg + S = MgS

(24g) (32g) (56g)

24 g of Mg reacts with 32 g of S.

So, 2 g of Mg will react with (32x2)/24 = 2.67 g of S.

The amount of S given (2g) is less than the required amount, thus S is the limiting reagent. The amount of MgS formed will depend upon the amount of S.

32 g of S gives 56 g of MgS

Therefore, 2 g of S will give (56x2)/32 = 3.5 g of MgS

Hope you understand