Question

The amount of oxygen formed when 12.26 g of KClO3 is heated what is the answer with solution

Answer 1

Answer:

The amount of oxygen formed when 12.26 g of kclo3 is heated is

∴ 12.26 of KClO₃ forms 32/245 × 12.26 g = 1.60 g of Oxygen. Hence, the mass of theOxygen evolved in this case is 1.6 g. Hope it helps.

Answer 2

When pottasium chlorate is heated oxygen and pottasium chlorite is produced .

two moles of pottasium chlorate produce two moles of pottasium chlorite and three moles of oxygen

the molecular weight of the pottasium chlorate is ( 39+35.5+48)= 122.5 g

molecular weight of oxygen is 16×2 = 32 g

molecular weight of pottasium chlorite is (39+35.5) = 74.5 g

so 2× 122.5 gm KClO3 produces 32 gm of O2

so 12.26 gm KClO3 produces {12.26× (32/245) } = 1.6 gm of oxygen (O2)