The amount of oxygen required to combust the 120gms of carbon
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Answer:
C+O2-------------CO2
moles of carbon =240/12=20mol
mole ratio of carbon and oxygen is 1:1
so moles of oxgen is 20mol.
20*24=480dm^3 of oxygen is needed to combust with the 120 gms of carbon at room temperature (rtp).
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Answered by
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Answer:
C+O2--->CO2
So, for 1 mole of C, 1 mole of O2 of required, that is
for 12 g of C, (16*2) g of oxygen is required.
12g--->32g
120g-->Xg is required.
X=(120*32)/12
=3840/12
=320
Therefore, 320g of Oxygen is required.
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