Question

The amount of U235 to be fissioned, to operate 10kW nuclear reactor is (Approximately)(1) 1.2 x 10-5 g/s(2) 1.2 x 10-7 g/s(3) 1.2 x 10-9 g/s(4) 1.2 x 10-13 g/s​

Answer 1

Answer:(2) 1.2X10-7

Explanation:

Answer 2

Given :

U 235 fissioned to operate  10 kW nuclear reactor.

To Find:

Mass of U235 required to operate 10kW nuclear reactor

The Fission of a  U235 nucleus releases 200MeV of energy.

A nuclear reactor is to be operated by using energy released from fission of

U 235 .

fission of 1 nucleus = 200MeV energy

fission of X nucleus= 10kW

1 eV= 1.6 × $10^{-19}$ joules

fission of 1 nucleus= $(200)$$10^{6}(1.6)(10^{-19} )$

                              = $320$ ×$10^{-13}$ joules

N(320 ×$(10^{-13}) = 10000$

N = 31.25×$10^{13}$

no of molecules = no. of moles ×avagadro number

n = 5.15×$10^{-10}$

n× molar mass = mass of U235

$5.15 (10^{-10} )(235)= m\\m = 1.2 (10^{-7} ) kg$

Mass of U235 required is equal to 1.2×$10^{-7}$ kg